提交 27e639bf 编写于 作者: V Ville Syrjälä 提交者: Daniel Vetter

drm/i915: Make sure we respect n.max on VLV

We limit the maximum n divider value in order to make sure the PLL's
reference inout is at least 19.2 MHz. I assume that is done to satisfy
some hardware requirement.

However we never check whether that calculated limit is below the
maximum supoorted N divider value (7). In practice that is always true
since we only support 100 MHz reference clock, but making the code
safe against higher reference clocks seems like a reasoanble thing to
do.
Signed-off-by: NVille Syrjälä <ville.syrjala@linux.intel.com>
Reviewed-by: NMika Kuoppala <mika.kuoppala@intel.com>
Signed-off-by: NDaniel Vetter <daniel.vetter@ffwll.ch>
上级 c1a9ae43
...@@ -678,15 +678,16 @@ vlv_find_best_dpll(const intel_limit_t *limit, struct drm_crtc *crtc, ...@@ -678,15 +678,16 @@ vlv_find_best_dpll(const intel_limit_t *limit, struct drm_crtc *crtc,
intel_clock_t *best_clock) intel_clock_t *best_clock)
{ {
intel_clock_t clock; intel_clock_t clock;
u32 minupdate = 19200;
unsigned int bestppm = 1000000; unsigned int bestppm = 1000000;
/* min update 19.2 MHz */
int max_n = min(limit->n.max, refclk / 19200);
target *= 5; /* fast clock */ target *= 5; /* fast clock */
memset(best_clock, 0, sizeof(*best_clock)); memset(best_clock, 0, sizeof(*best_clock));
/* based on hardware requirement, prefer smaller n to precision */ /* based on hardware requirement, prefer smaller n to precision */
for (clock.n = limit->n.min; clock.n <= ((refclk) / minupdate); clock.n++) { for (clock.n = limit->n.min; clock.n <= max_n; clock.n++) {
for (clock.p1 = limit->p1.max; clock.p1 > limit->p1.min; clock.p1--) { for (clock.p1 = limit->p1.max; clock.p1 > limit->p1.min; clock.p1--) {
for (clock.p2 = limit->p2.p2_fast; clock.p2 > 0; for (clock.p2 = limit->p2.p2_fast; clock.p2 > 0;
clock.p2 -= clock.p2 > 10 ? 2 : 1) { clock.p2 -= clock.p2 > 10 ? 2 : 1) {
......
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