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由 Jacob Keller 提交于
We can simply check both Tx and Rx queues in a single loop, rather than repeating the loop twice. Change-ID: Ic06f26b0e3c2620e0e33c1a2999edda488e647ad Signed-off-by: NJacob Keller <jacob.e.keller@intel.com> Tested-by: NAndrew Bowers <andrewx.bowers@intel.com> Signed-off-by: NJeff Kirsher <jeffrey.t.kirsher@intel.com>
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