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    Btrfs: allocate the free space by the existed max extent size when ENOSPC · a4820398
    Miao Xie 提交于
    By the current code, if the requested size is very large, and all the extents
    in the free space cache are small, we will waste lots of the cpu time to cut
    the requested size in half and search the cache again and again until it gets
    down to the size the allocator can return. In fact, we can know the max extent
    size in the cache after the first search, so we needn't cut the size in half
    repeatedly, and just use the max extent size directly. This way can save
    lots of cpu time and make the performance grow up when there are only fragments
    in the free space cache.
    
    According to my test, if there are only 4KB free space extents in the fs,
    and the total size of those extents are 256MB, we can reduce the execute
    time of the following test from 5.4s to 1.4s.
      dd if=/dev/zero of=<testfile> bs=1MB count=1 oflag=sync
    
    Changelog v2 -> v3:
    - fix the problem that we skip the block group with the space which is
      less than we need.
    
    Changelog v1 -> v2:
    - address the problem that we return a wrong start position when searching
      the free space in a bitmap.
    Signed-off-by: NMiao Xie <miaox@cn.fujitsu.com>
    Signed-off-by: NJosef Bacik <jbacik@fusionio.com>
    Signed-off-by: NChris Mason <chris.mason@fusionio.com>
    a4820398
free-space-cache.c 76.7 KB