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由 David S. Miller 提交于
Based almost entirely upon a patch by Eric Dumazet. The common case is to have num-tx-queues <= num_rx_queues and even if num_tx_queues is larger it will not be significantly larger. Therefore, a subtraction loop is always going to be faster than modulus. Signed-off-by: NDavid S. Miller <davem@davemloft.net>
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