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    sh: Add plain udivsi3 (not _i4*) for gcc-4.1 and lower. · 3b041227
    Takashi YOSHII 提交于
    We chan't share code for udivsi3 and udivsi3_i4, because they
    have a different clobber list. Copy udivsi3 from gcc-4.1.2.
    
    As shown in arch/sh/lib/udivsi3.S (and -Os.S),
    
      .global __udivsi3_i4i
      .global __udivsi3_i4
      .global __udivsi3
    __udivsi3_i4i:
      ...
    
    Three symbols are sharing one code, which is actually udivsi3_i4i.
    But, this results unwanted code with gcc 4.1.
    
    In gcc, these three are treated as pseudo instructions that have
    their own clobber list apart from the usual calling convention.
    
    According to sh's machine description. The clobber list is as
    follows:
    
     - udivsi3_i4i : t,r1,pr,mach,macl
     - udivsi3_i4  : t,r0,r1,r4,r5,pr,dr0,dr2,dr4
     - udivsi3     : t,r4,pr
    
    The caller of udivsi3 will be left with a broken r1 and mac*.
    
    gcc-4.1.x and older(at least to 3.4) generate udivsi3.
    ST's gcc-4.1.1 seems to be OK because it has _i4i.
    Signed-off-by: NTakashi YOSHII <yoshii.takashi@renesas.com>
    Signed-off-by: NPaul Mundt <lethal@linux-sh.org>
    3b041227
udivsi3.S 2.1 KB