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由 Darrick J. Wong 提交于
A bg that's been flagged "corrupt" by definition has no free blocks, so that the allocator won't be tempted to use the damaged bg. Therefore, we shouldn't count the clusters in the damaged group when calculating free counts. Signed-off-by: NDarrick J. Wong <darrick.wong@oracle.com> Signed-off-by: N"Theodore Ts'o" <tytso@mit.edu> Reviewed-by: NZheng Liu <wenqing.lz@taobao.com>
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