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由 Dimitris Papastamos 提交于
There is no need to use '&' in this case. Either way, if a is an array of some type, then a == &a == &a[0]. Signed-off-by: NDimitris Papastamos <dp@opensource.wolfsonmicro.com> Acked-by: NLiam Girdwood <lrg@slimlogic.co.uk> Signed-off-by: NMark Brown <broonie@opensource.wolfsonmicro.com>
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