提交 9c526812 编写于 作者: M Max Reitz 提交者: Kevin Wolf

qdict: Add qdict_join()

This function joins two QDicts by absorbing one into the other.
Signed-off-by: NMax Reitz <mreitz@redhat.com>
Reviewed-by: NBenoit Canet <benoit@irqsave.net>
Reviewed-by: NEric Blake <eblake@redhat.com>
Signed-off-by: NKevin Wolf <kwolf@redhat.com>
上级 26e2da72
......@@ -16,6 +16,7 @@
#include "qapi/qmp/qobject.h"
#include "qapi/qmp/qlist.h"
#include "qemu/queue.h"
#include <stdbool.h>
#include <stdint.h>
#define QDICT_BUCKET_MAX 512
......@@ -70,4 +71,6 @@ void qdict_flatten(QDict *qdict);
void qdict_extract_subqdict(QDict *src, QDict **dst, const char *start);
void qdict_array_split(QDict *src, QList **dst);
void qdict_join(QDict *dest, QDict *src, bool overwrite);
#endif /* QDICT_H */
......@@ -665,3 +665,35 @@ void qdict_array_split(QDict *src, QList **dst)
qlist_append_obj(*dst, subqobj ?: QOBJECT(subqdict));
}
}
/**
* qdict_join(): Absorb the src QDict into the dest QDict, that is, move all
* elements from src to dest.
*
* If an element from src has a key already present in dest, it will not be
* moved unless overwrite is true.
*
* If overwrite is true, the conflicting values in dest will be discarded and
* replaced by the corresponding values from src.
*
* Therefore, with overwrite being true, the src QDict will always be empty when
* this function returns. If overwrite is false, the src QDict will be empty
* iff there were no conflicts.
*/
void qdict_join(QDict *dest, QDict *src, bool overwrite)
{
const QDictEntry *entry, *next;
entry = qdict_first(src);
while (entry) {
next = qdict_next(src, entry);
if (overwrite || !qdict_haskey(dest, entry->key)) {
qobject_incref(entry->value);
qdict_put_obj(dest, entry->key, entry->value);
qdict_del(src, entry->key);
}
entry = next;
}
}
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