提交 682775fb 编写于 作者: E Erik Skultety

vsh: Make vshInitDebug static

There's no reason why debug initialization could not be made completely
hidden, just like readline initialization is. The point of the global
initializer vshInit is to make initialization of smaller features transparent
to the user/caller.
上级 a02de849
...@@ -2680,7 +2680,7 @@ vshReadline(vshControl *ctl, const char *prompt) ...@@ -2680,7 +2680,7 @@ vshReadline(vshControl *ctl, const char *prompt)
/* /*
* Initialize debug settings. * Initialize debug settings.
*/ */
void static void
vshInitDebug(vshControl *ctl) vshInitDebug(vshControl *ctl)
{ {
const char *debugEnv; const char *debugEnv;
......
...@@ -305,7 +305,6 @@ void vshPrintExtra(vshControl *ctl, const char *format, ...) ...@@ -305,7 +305,6 @@ void vshPrintExtra(vshControl *ctl, const char *format, ...)
bool vshInit(vshControl *ctl, const vshCmdGrp *groups, const vshCmdDef *set); bool vshInit(vshControl *ctl, const vshCmdGrp *groups, const vshCmdDef *set);
bool vshInitReload(vshControl *ctl); bool vshInitReload(vshControl *ctl);
void vshDeinit(vshControl *ctl); void vshDeinit(vshControl *ctl);
void vshInitDebug(vshControl *ctl);
void vshDebug(vshControl *ctl, int level, const char *format, ...) void vshDebug(vshControl *ctl, int level, const char *format, ...)
ATTRIBUTE_FMT_PRINTF(3, 4); ATTRIBUTE_FMT_PRINTF(3, 4);
......
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