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由 Michal Privoznik 提交于
This is only a theoretical leak, but in virChrdevAlloc() we initialize a mutex and if creating a hash table fails, then virChrdevFree() is called which because of incorrect check doesn't deinit the mutex. Signed-off-by: NMichal Privoznik <mprivozn@redhat.com> Reviewed-by: NErik Skultety <eskultet@redhat.com>
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