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  1. 11 9月, 2020 3 次提交
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  35. 05 9月, 2019 1 次提交
    • G
      Bluetooth: mgmt: Use struct_size() helper · 72bb169e
      由 Gustavo A. R. Silva 提交于 
      One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct mgmt_rp_get_connections {
	...
        struct mgmt_addr_info addr[0];
} __packed;

Make use of the struct_size() helper instead of an open-coded version
in order to avoid any potential type mistakes.

So, replace the following form:

sizeof(*rp) + (i * sizeof(struct mgmt_addr_info));

with:

struct_size(rp, addr, i)

Also, notice that, in this case, variable rp_len is not necessary,
hence it is removed.

This code was detected with the help of Coccinelle.
Signed-off-by: NGustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: NMarcel Holtmann <marcel@holtmann.org>
      72bb169e
  37. 24 4月, 2019 1 次提交
    • G
      Bluetooth: Use struct_size() helper · 5bec1fb8
      由 Gustavo A. R. Silva 提交于 
      One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    struct boo entry[];
};

size = sizeof(struct foo) + count * sizeof(struct boo);

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

size = struct_size(instance, entry, count);

This code was detected with the help of Coccinelle.
Signed-off-by: NGustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: NMarcel Holtmann <marcel@holtmann.org>
      5bec1fb8
  39. 26 2月, 2019 2 次提交