提交 fe03a9f7 编写于 作者: H Hans J. Koch 提交者: Thomas Gleixner

arm: tcc8k: Fix clock rate calculation

The calculation of the best divider value for a requested clock rate
always returned a value that was slightly too large. It was also not
protected against possible divisions by zero.

Request for very low, but non zero rates would cause the ACLK divisor
field to overflow. Catch this situation by using the maximum value.

The internal function aclk_set_rate() calculates the correct divider
value, but doesn't write it back to the register. Add the write back.
Signed-off-by: NHans J. Koch <hjk@linutronix.de>
Signed-off-by: NOskar Schirmer <oskar@linutronix.de>
Cc: bigeasy@linutronix.de
Signed-off-by: NThomas Gleixner <tglx@linutronix.de>
上级 85922e54
......@@ -50,6 +50,8 @@
#define ACLKTCX (CKC_BASE + ACLKTCX_OFFS)
#define ACLKTCZ (CKC_BASE + ACLKTCZ_OFFS)
#define ACLK_MAX_DIV (0xfff + 1)
/* Crystal frequencies */
static unsigned long xi_rate, xti_rate;
......@@ -258,14 +260,19 @@ static unsigned long aclk_best_div(struct clk *clk, unsigned long rate)
{
unsigned long div, src, freq, r1, r2;
if (!rate)
return ACLK_MAX_DIV;
src = __raw_readl(clk->aclkreg) >> ACLK_SEL_SHIFT;
src &= CLK_SRC_MASK;
freq = root_clk_get_rate(src);
div = freq / rate + 1;
div = freq / rate;
if (!div)
return 1;
if (div >= ACLK_MAX_DIV)
return ACLK_MAX_DIV;
r1 = freq / div;
r2 = freq / (div + 1);
if (r2 >= rate)
return div + 1;
if ((rate - r2) < (r1 - rate))
return div + 1;
......@@ -287,7 +294,8 @@ static int aclk_set_rate(struct clk *clk, unsigned long rate)
u32 reg;
reg = __raw_readl(clk->aclkreg) & ~ACLK_DIV_MASK;
reg |= aclk_best_div(clk, rate);
reg |= aclk_best_div(clk, rate) - 1;
__raw_writel(reg, clk->aclkreg);
return 0;
}
......
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