net: macb: Free RX ring for all queues

rx ring is allocated for all queues in macb_alloc_consistent.
Free the same for all queues instead of just Q0.
Signed-off-by: NHarini Katakam <harini.katakam@xilinx.com>
Reviewed-by: NClaudiu Beznea <claudiu.beznea@microchip.com>
Signed-off-by: NDavid S. Miller <davem@davemloft.net>

drivers/net/ethernet/cadence/macb_main.c

@@ -1812,13 +1812,7 @@ static void macb_free_consistent(struct macb *bp)
 	struct macb_queue *queue;
 	unsigned int q;
 
-	queue = &bp->queues[0];
 	bp->macbgem_ops.mog_free_rx_buffers(bp);
-	if (queue->rx_ring) {
-		dma_free_coherent(&bp->pdev->dev, RX_RING_BYTES(bp),
-				queue->rx_ring, queue->rx_ring_dma);
-		queue->rx_ring = NULL;
-	}
 
 	for (q = 0, queue = bp->queues; q < bp->num_queues; ++q, ++queue) {
 		kfree(queue->tx_skb);
@@ -1828,6 +1822,11 @@ static void macb_free_consistent(struct macb *bp)
 					  queue->tx_ring, queue->tx_ring_dma);
 			queue->tx_ring = NULL;
 		}
+		if (queue->rx_ring) {
+			dma_free_coherent(&bp->pdev->dev, RX_RING_BYTES(bp),
+					  queue->rx_ring, queue->rx_ring_dma);
+			queue->rx_ring = NULL;
+		}
 	}
 }