btrfs: volumes: Remove the meaningless condition of minimal nr_devs when allocating a chunk

When checking the minimal nr_devs, there is one dead and meaningless
condition:

if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This condition is meaningless, @devs_increment has nothing to do with
@sub_stripes.

In fact, in btrfs_raid_array[], profile with sub_stripes larger than 1
(RAID10) already has the @devs_increment set to 2.
So no need to multiple it by @sub_stripes.

And above condition is also dead.
For RAID10, @devs_increment * @sub_stripes equals 4, which is also the
@devs_min of RAID10.
For other profiles, @sub_stripes is always 1, and since @ndevs is
rounded down to @devs_increment, the condition will always be true.

Remove the meaningless condition to make later reader wander less.
Signed-off-by: NQu Wenruo <wqu@suse.com>
Reviewed-by: NNikolay Borisov <nborisov@suse.com>
Reviewed-by: NDavid Sterba <dsterba@suse.com>
Signed-off-by: NDavid Sterba <dsterba@suse.com>

fs/btrfs/volumes.c

@@ -4837,13 +4837,12 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
 	/* round down to number of usable stripes */
 	ndevs = round_down(ndevs, devs_increment);
 
-	if (ndevs < devs_increment * sub_stripes || ndevs < devs_min) {
+	if (ndevs < devs_min) {
 		ret = -ENOSPC;
 		if (btrfs_test_opt(info, ENOSPC_DEBUG)) {
 			btrfs_debug(info,
 	"%s: not enough devices with free space: have=%d minimum required=%d",
-				    __func__, ndevs, min(devs_min,
-				    devs_increment * sub_stripes));
+				    __func__, ndevs, devs_min);
 		}
 		goto error;
 	}