提交 b9fa6442 编写于 作者: T Thomas Gleixner

cpumask: Implement cpumask_or_equal()

The IPI code of x86 needs to evaluate whether the target cpumask is equal
to the cpu_online_mask or equal except for the calling CPU.

To replace the current implementation which requires the usage of a
temporary cpumask, which might involve allocations, add a new function
which compares a cpumask to the result of two other cpumasks which are
or'ed together before comparison.

This allows to make the required decision in one go and the calling code
then can check for the calling CPU being set in the target mask with
cpumask_test_cpu().
Signed-off-by: NThomas Gleixner <tglx@linutronix.de>
Acked-by: NPeter Zijlstra (Intel) <peterz@infradead.org>
Link: https://lkml.kernel.org/r/20190722105220.585449120@linutronix.de
上级 e797bda3
......@@ -120,6 +120,10 @@ extern int __bitmap_empty(const unsigned long *bitmap, unsigned int nbits);
extern int __bitmap_full(const unsigned long *bitmap, unsigned int nbits);
extern int __bitmap_equal(const unsigned long *bitmap1,
const unsigned long *bitmap2, unsigned int nbits);
extern bool __pure __bitmap_or_equal(const unsigned long *src1,
const unsigned long *src2,
const unsigned long *src3,
unsigned int nbits);
extern void __bitmap_complement(unsigned long *dst, const unsigned long *src,
unsigned int nbits);
extern void __bitmap_shift_right(unsigned long *dst, const unsigned long *src,
......@@ -321,6 +325,25 @@ static inline int bitmap_equal(const unsigned long *src1,
return __bitmap_equal(src1, src2, nbits);
}
/**
* bitmap_or_equal - Check whether the or of two bitnaps is equal to a third
* @src1: Pointer to bitmap 1
* @src2: Pointer to bitmap 2 will be or'ed with bitmap 1
* @src3: Pointer to bitmap 3. Compare to the result of *@src1 | *@src2
*
* Returns: True if (*@src1 | *@src2) == *@src3, false otherwise
*/
static inline bool bitmap_or_equal(const unsigned long *src1,
const unsigned long *src2,
const unsigned long *src3,
unsigned int nbits)
{
if (!small_const_nbits(nbits))
return __bitmap_or_equal(src1, src2, src3, nbits);
return !(((*src1 | *src2) ^ *src3) & BITMAP_LAST_WORD_MASK(nbits));
}
static inline int bitmap_intersects(const unsigned long *src1,
const unsigned long *src2, unsigned int nbits)
{
......
......@@ -475,6 +475,20 @@ static inline bool cpumask_equal(const struct cpumask *src1p,
nr_cpumask_bits);
}
/**
* cpumask_or_equal - *src1p | *src2p == *src3p
* @src1p: the first input
* @src2p: the second input
* @src3p: the third input
*/
static inline bool cpumask_or_equal(const struct cpumask *src1p,
const struct cpumask *src2p,
const struct cpumask *src3p)
{
return bitmap_or_equal(cpumask_bits(src1p), cpumask_bits(src2p),
cpumask_bits(src3p), nr_cpumask_bits);
}
/**
* cpumask_intersects - (*src1p & *src2p) != 0
* @src1p: the first input
......
......@@ -59,6 +59,26 @@ int __bitmap_equal(const unsigned long *bitmap1,
}
EXPORT_SYMBOL(__bitmap_equal);
bool __bitmap_or_equal(const unsigned long *bitmap1,
const unsigned long *bitmap2,
const unsigned long *bitmap3,
unsigned int bits)
{
unsigned int k, lim = bits / BITS_PER_LONG;
unsigned long tmp;
for (k = 0; k < lim; ++k) {
if ((bitmap1[k] | bitmap2[k]) != bitmap3[k])
return false;
}
if (!(bits % BITS_PER_LONG))
return true;
tmp = (bitmap1[k] | bitmap2[k]) ^ bitmap3[k];
return (tmp & BITMAP_LAST_WORD_MASK(bits)) == 0;
}
void __bitmap_complement(unsigned long *dst, const unsigned long *src, unsigned int bits)
{
unsigned int k, lim = BITS_TO_LONGS(bits);
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册