SELinux: fix selinuxfs policy file on big endian systems
The /sys/fs/selinux/policy file is not valid on big endian systems like ppc64 or s390. Let's see why: static int hashtab_cnt(void *key, void *data, void *ptr) { int *cnt = ptr; *cnt = *cnt + 1; return 0; } static int range_write(struct policydb *p, void *fp) { size_t nel; [...] /* count the number of entries in the hashtab */ nel = 0; rc = hashtab_map(p->range_tr, hashtab_cnt, &nel); if (rc) return rc; buf[0] = cpu_to_le32(nel); rc = put_entry(buf, sizeof(u32), 1, fp); So size_t is 64 bits. But then we pass a pointer to it as we do to hashtab_cnt. hashtab_cnt thinks it is a 32 bit int and only deals with the first 4 bytes. On x86_64 which is little endian, those first 4 bytes and the least significant, so this works out fine. On ppc64/s390 those first 4 bytes of memory are the high order bits. So at the end of the call to hashtab_map nel has a HUGE number. But the least significant 32 bits are all 0's. We then pass that 64 bit number to cpu_to_le32() which happily truncates it to a 32 bit number and does endian swapping. But the low 32 bits are all 0's. So no matter how many entries are in the hashtab, big endian systems always say there are 0 entries because I screwed up the counting. The fix is easy. Use a 32 bit int, as the hashtab_cnt expects, for nel. Signed-off-by: NEric Paris <eparis@redhat.com> Signed-off-by: NPaul Moore <pmoore@redhat.com>
Showing
想要评论请 注册 或 登录