btrfs: Don't hardcode the csum size in btrfs_ordered_sum_size

Currently the function uses a hardcoded value for the checksum size of
a sector. This is fine, given that we currently support only a single
algorithm, whose checksum is 4 bytes == sizeof(u32). Despite not
having other algorithms, btrfs' design supports using a different
algorithm whith different space requirements. To future-proof the code
query the size of the currently used algorithm from the in-memory copy
of the super block. No functional changes.
Signed-off-by: NNikolay Borisov <nborisov@suse.com>
Reviewed-by: NQu Wenruo <wqu@suse.com>
Reviewed-by: NSu Yue <suy.fnst@cn.fujitsu.com>
Signed-off-by: NDavid Sterba <dsterba@suse.com>

fs/btrfs/ordered-data.h

@@ -151,7 +151,9 @@ static inline int btrfs_ordered_sum_size(struct btrfs_fs_info *fs_info,
 					 unsigned long bytes)
 {
 	int num_sectors = (int)DIV_ROUND_UP(bytes, fs_info->sectorsize);
-	return sizeof(struct btrfs_ordered_sum) + num_sectors * sizeof(u32);
+	int csum_size = btrfs_super_csum_size(fs_info->super_copy);
+
+	return sizeof(struct btrfs_ordered_sum) + num_sectors * csum_size;
 }
 
 static inline void