Skip to content
体验新版
项目
组织
正在加载...
登录
切换导航
打开侧边栏
openeuler
Kernel
提交
a8e5202d
K
Kernel
项目概览
openeuler
/
Kernel
1 年多 前同步成功
通知
8
Star
0
Fork
0
代码
文件
提交
分支
Tags
贡献者
分支图
Diff
Issue
0
列表
看板
标记
里程碑
合并请求
0
DevOps
流水线
流水线任务
计划
Wiki
0
Wiki
分析
仓库
DevOps
项目成员
Pages
K
Kernel
项目概览
项目概览
详情
发布
仓库
仓库
文件
提交
分支
标签
贡献者
分支图
比较
Issue
0
Issue
0
列表
看板
标记
里程碑
合并请求
0
合并请求
0
Pages
DevOps
DevOps
流水线
流水线任务
计划
分析
分析
仓库分析
DevOps
Wiki
0
Wiki
成员
成员
收起侧边栏
关闭侧边栏
动态
分支图
创建新Issue
流水线任务
提交
Issue看板
提交
a8e5202d
编写于
6月 23, 2012
作者:
C
Cong Wang
浏览文件
操作
浏览文件
下载
电子邮件补丁
差异文件
vmalloc: remove KM_USER0 from comments
Signed-off-by:
N
Cong Wang
<
amwang@redhat.com
>
上级
167885e5
变更
1
隐藏空白更改
内联
并排
Showing
1 changed file
with
2 addition
and
6 deletion
+2
-6
mm/vmalloc.c
mm/vmalloc.c
+2
-6
未找到文件。
mm/vmalloc.c
浏览文件 @
a8e5202d
...
...
@@ -1975,9 +1975,7 @@ static int aligned_vwrite(char *buf, char *addr, unsigned long count)
* IOREMAP area is treated as memory hole and no copy is done.
*
* If [addr...addr+count) doesn't includes any intersects with alive
* vm_struct area, returns 0.
* @buf should be kernel's buffer. Because this function uses KM_USER0,
* the caller should guarantee KM_USER0 is not used.
* vm_struct area, returns 0. @buf should be kernel's buffer.
*
* Note: In usual ops, vread() is never necessary because the caller
* should know vmalloc() area is valid and can use memcpy().
...
...
@@ -2051,9 +2049,7 @@ long vread(char *buf, char *addr, unsigned long count)
* IOREMAP area is treated as memory hole and no copy is done.
*
* If [addr...addr+count) doesn't includes any intersects with alive
* vm_struct area, returns 0.
* @buf should be kernel's buffer. Because this function uses KM_USER0,
* the caller should guarantee KM_USER0 is not used.
* vm_struct area, returns 0. @buf should be kernel's buffer.
*
* Note: In usual ops, vwrite() is never necessary because the caller
* should know vmalloc() area is valid and can use memcpy().
...
...
编辑
预览
Markdown
is supported
0%
请重试
或
添加新附件
.
添加附件
取消
You are about to add
0
people
to the discussion. Proceed with caution.
先完成此消息的编辑!
取消
想要评论请
注册
或
登录