igb: override two checker warnings

The igb PTP code was using htons() on a constant to try to
byte swap the value before writing it to a register. This byte
swap has the consequence of triggering sparse conflicts between
the register write which expect cpu ordered input, and the code
which generated a big endian constant. Just override the cast
to make sure code doesn't change but silence the warning.

Can't do a __swab16 in this case because big endian systems
would then write the wrong value.
Signed-off-by: NJesse Brandeburg <jesse.brandeburg@intel.com>
Tested-by: NDave Switzer <david.switzer@intel.com>
Signed-off-by: NTony Nguyen <anthony.l.nguyen@intel.com>

drivers/net/ethernet/intel/igb/igb_ptp.c

@@ -1134,12 +1134,12 @@ static int igb_ptp_set_timestamp_mode(struct igb_adapter *adapter,
 			| E1000_FTQF_MASK); /* mask all inputs */
 		ftqf &= ~E1000_FTQF_MASK_PROTO_BP; /* enable protocol check */
 
-		wr32(E1000_IMIR(3), htons(PTP_EV_PORT));
+		wr32(E1000_IMIR(3), (__force unsigned int)htons(PTP_EV_PORT));
 		wr32(E1000_IMIREXT(3),
 		     (E1000_IMIREXT_SIZE_BP | E1000_IMIREXT_CTRL_BP));
 		if (hw->mac.type == e1000_82576) {
 			/* enable source port check */
-			wr32(E1000_SPQF(3), htons(PTP_EV_PORT));
+			wr32(E1000_SPQF(3), (__force unsigned int)htons(PTP_EV_PORT));
 			ftqf &= ~E1000_FTQF_MASK_SOURCE_PORT_BP;
 		}
 		wr32(E1000_FTQF(3), ftqf);