提交 8b01f931 编写于 作者: F Filipe Manana 提交者: David Sterba

btrfs: return block group directly at btrfs_next_block_group()

At btrfs_next_block_group(), we have this long line with two statements:

  cache = btrfs_lookup_first_block_group(...); return cache;

This makes it a bit harder to read due to two statements on the same
line, so change that to directly return the result of the call to
btrfs_lookup_first_block_group().
Reviewed-by: NNikolay Borisov <nborisov@suse.com>
Signed-off-by: NFilipe Manana <fdmanana@suse.com>
Reviewed-by: NDavid Sterba <dsterba@suse.com>
Signed-off-by: NDavid Sterba <dsterba@suse.com>
上级 16b0c258
......@@ -271,7 +271,7 @@ struct btrfs_block_group *btrfs_next_block_group(
read_unlock(&fs_info->block_group_cache_lock);
btrfs_put_block_group(cache);
cache = btrfs_lookup_first_block_group(fs_info, next_bytenr); return cache;
return btrfs_lookup_first_block_group(fs_info, next_bytenr);
}
node = rb_next(&cache->cache_node);
btrfs_put_block_group(cache);
......
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