提交 64dcc7c2 编写于 作者: C Christoph Hellwig 提交者: Jens Axboe

block: use bdev_alignment_offset in part_alignment_offset_show

Replace the open coded offset calculation with the proper helper.
This is an ABI change in that the -1 for a misaligned partition is
properly propagated, which can be considered a bug fix and matches
what is done on the whole device.
Signed-off-by: NChristoph Hellwig <hch@lst.de>
Reviewed-by: NMartin K. Petersen <martin.petersen@oracle.com>
Reviewed-by: NChaitanya Kulkarni <kch@nvidia.com>
Link: https://lore.kernel.org/r/20220415045258.199825-17-hch@lst.deSigned-off-by: NJens Axboe <axboe@kernel.dk>
上级 2aba0d19
......@@ -200,11 +200,7 @@ static ssize_t part_ro_show(struct device *dev,
static ssize_t part_alignment_offset_show(struct device *dev,
struct device_attribute *attr, char *buf)
{
struct block_device *bdev = dev_to_bdev(dev);
return sprintf(buf, "%u\n",
queue_limit_alignment_offset(&bdev_get_queue(bdev)->limits,
bdev->bd_start_sect));
return sprintf(buf, "%u\n", bdev_alignment_offset(dev_to_bdev(dev)));
}
static ssize_t part_discard_alignment_show(struct device *dev,
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册