block: move bdput() to the callers of __blkdev_get

This will allow for a more symmetric calling convention going forward.
Signed-off-by: NChristoph Hellwig <hch@lst.de>
Reviewed-by: NJan Kara <jack@suse.cz>
Reviewed-by: NHannes Reinecke <hare@suse.de>
Signed-off-by: NJens Axboe <axboe@kernel.dk>

fs/block_dev.c

@@ -1462,6 +1462,7 @@ static int __blkdev_get(struct block_device *bdev, struct gendisk *disk,
 			if (!(disk->flags & GENHD_FL_UP) ||
 			    !bdev->bd_part || !bdev->bd_part->nr_sects) {
 				__blkdev_put(whole, mode, 1);
+				bdput(whole);
 				ret = -ENXIO;
 				goto out_clear;
 			}
@@ -1744,9 +1745,10 @@ static void __blkdev_put(struct block_device *bdev, fmode_t mode, int for_part)
 			disk->fops->release(disk, mode);
 	}
 	mutex_unlock(&bdev->bd_mutex);
-	bdput(bdev);
-	if (victim)
+	if (victim) {
 		__blkdev_put(victim, mode, 1);
+		bdput(victim);
+	}
 }
 
 void blkdev_put(struct block_device *bdev, fmode_t mode)
@@ -1796,6 +1798,7 @@ void blkdev_put(struct block_device *bdev, fmode_t mode)
 	mutex_unlock(&bdev->bd_mutex);
 
 	__blkdev_put(bdev, mode, 0);
+	bdput(bdev);
 	put_disk_and_module(disk);
 }
 EXPORT_SYMBOL(blkdev_put);