提交 6364e67e 编写于 作者: J Jani Nikula 提交者: Daniel Vetter

drm/i915: don't register invalid gmbus pins for skl

Do not expose invalid gmbus pins as i2c devices to userspace.
Signed-off-by: NJani Nikula <jani.nikula@intel.com>
Reviewed-by: NImre Deak <imre.deak@intel.com>
Signed-off-by: NDaniel Vetter <daniel.vetter@ffwll.ch>
上级 c1bad5b6
...@@ -56,6 +56,12 @@ static const struct gmbus_pin gmbus_pins_bdw[] = { ...@@ -56,6 +56,12 @@ static const struct gmbus_pin gmbus_pins_bdw[] = {
[GMBUS_PIN_DPD] = { "dpd", GPIOF }, [GMBUS_PIN_DPD] = { "dpd", GPIOF },
}; };
static const struct gmbus_pin gmbus_pins_skl[] = {
[GMBUS_PIN_DPC] = { "dpc", GPIOD },
[GMBUS_PIN_DPB] = { "dpb", GPIOE },
[GMBUS_PIN_DPD] = { "dpd", GPIOF },
};
static const struct gmbus_pin gmbus_pins_bxt[] = { static const struct gmbus_pin gmbus_pins_bxt[] = {
[GMBUS_PIN_1_BXT] = { "dpb", PCH_GPIOB }, [GMBUS_PIN_1_BXT] = { "dpb", PCH_GPIOB },
[GMBUS_PIN_2_BXT] = { "dpc", PCH_GPIOC }, [GMBUS_PIN_2_BXT] = { "dpc", PCH_GPIOC },
...@@ -68,6 +74,8 @@ static const struct gmbus_pin *get_gmbus_pin(struct drm_i915_private *dev_priv, ...@@ -68,6 +74,8 @@ static const struct gmbus_pin *get_gmbus_pin(struct drm_i915_private *dev_priv,
{ {
if (IS_BROXTON(dev_priv)) if (IS_BROXTON(dev_priv))
return &gmbus_pins_bxt[pin]; return &gmbus_pins_bxt[pin];
else if (IS_SKYLAKE(dev_priv))
return &gmbus_pins_skl[pin];
else if (IS_BROADWELL(dev_priv)) else if (IS_BROADWELL(dev_priv))
return &gmbus_pins_bdw[pin]; return &gmbus_pins_bdw[pin];
else else
...@@ -81,6 +89,8 @@ bool intel_gmbus_is_valid_pin(struct drm_i915_private *dev_priv, ...@@ -81,6 +89,8 @@ bool intel_gmbus_is_valid_pin(struct drm_i915_private *dev_priv,
if (IS_BROXTON(dev_priv)) if (IS_BROXTON(dev_priv))
size = ARRAY_SIZE(gmbus_pins_bxt); size = ARRAY_SIZE(gmbus_pins_bxt);
else if (IS_SKYLAKE(dev_priv))
size = ARRAY_SIZE(gmbus_pins_skl);
else if (IS_BROADWELL(dev_priv)) else if (IS_BROADWELL(dev_priv))
size = ARRAY_SIZE(gmbus_pins_bdw); size = ARRAY_SIZE(gmbus_pins_bdw);
else else
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册