提交 5df6a9f6 编写于 作者: J Josef Bacik 提交者: Chris Mason

Btrfs: fix some metadata enospc issues

We weren't reserving metadata space for rename, rmdir and unlink, which could
cause problems.
Signed-off-by: NJosef Bacik <josef@redhat.com>
Signed-off-by: NChris Mason <chris.mason@oracle.com>
上级 01dea1ef
......@@ -2488,7 +2488,19 @@ static int btrfs_unlink(struct inode *dir, struct dentry *dentry)
root = BTRFS_I(dir)->root;
/*
* 5 items for unlink inode
* 1 for orphan
*/
ret = btrfs_reserve_metadata_space(root, 6);
if (ret)
return ret;
trans = btrfs_start_transaction(root, 1);
if (IS_ERR(trans)) {
btrfs_unreserve_metadata_space(root, 6);
return PTR_ERR(trans);
}
btrfs_set_trans_block_group(trans, dir);
......@@ -2503,6 +2515,7 @@ static int btrfs_unlink(struct inode *dir, struct dentry *dentry)
nr = trans->blocks_used;
btrfs_end_transaction_throttle(trans, root);
btrfs_unreserve_metadata_space(root, 6);
btrfs_btree_balance_dirty(root, nr);
return ret;
}
......@@ -2583,7 +2596,16 @@ static int btrfs_rmdir(struct inode *dir, struct dentry *dentry)
inode->i_ino == BTRFS_FIRST_FREE_OBJECTID)
return -ENOTEMPTY;
ret = btrfs_reserve_metadata_space(root, 5);
if (ret)
return ret;
trans = btrfs_start_transaction(root, 1);
if (IS_ERR(trans)) {
btrfs_unreserve_metadata_space(root, 5);
return PTR_ERR(trans);
}
btrfs_set_trans_block_group(trans, dir);
if (unlikely(inode->i_ino == BTRFS_EMPTY_SUBVOL_DIR_OBJECTID)) {
......@@ -2606,6 +2628,7 @@ static int btrfs_rmdir(struct inode *dir, struct dentry *dentry)
out:
nr = trans->blocks_used;
ret = btrfs_end_transaction_throttle(trans, root);
btrfs_unreserve_metadata_space(root, 5);
btrfs_btree_balance_dirty(root, nr);
if (ret && !err)
......@@ -5297,11 +5320,14 @@ static int btrfs_rename(struct inode *old_dir, struct dentry *old_dentry,
return -ENOTEMPTY;
/*
* 2 items for dir items
* 1 item for orphan entry
* 1 item for ref
* We want to reserve the absolute worst case amount of items. So if
* both inodes are subvols and we need to unlink them then that would
* require 4 item modifications, but if they are both normal inodes it
* would require 5 item modifications, so we'll assume their normal
* inodes. So 5 * 2 is 10, plus 1 for the new link, so 11 total items
* should cover the worst case number of items we'll modify.
*/
ret = btrfs_reserve_metadata_space(root, 4);
ret = btrfs_reserve_metadata_space(root, 11);
if (ret)
return ret;
......@@ -5417,7 +5443,7 @@ static int btrfs_rename(struct inode *old_dir, struct dentry *old_dentry,
if (old_inode->i_ino == BTRFS_FIRST_FREE_OBJECTID)
up_read(&root->fs_info->subvol_sem);
btrfs_unreserve_metadata_space(root, 4);
btrfs_unreserve_metadata_space(root, 11);
return ret;
}
......
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