提交 5d1ff106 编写于 作者: S Shannon Nelson 提交者: Jeff Kirsher

i40e: trigger SW INT with no ITR wait

Since we want the SW INT to go off as soon as possible, write the
extra bits that will turn off the ITR wait for the interrupt.

Change-ID: I6d5382ba60840fa32abb7dea17c839eb4b5f68f7
Signed-off-by: NShannon Nelson <shannon.nelson@intel.com>
Signed-off-by: NJeff Kirsher <jeffrey.t.kirsher@intel.com>
上级 c88e38cc
......@@ -1400,7 +1400,10 @@ static int i40e_intr_test(struct net_device *netdev, u64 *data)
netif_info(pf, hw, netdev, "interrupt test\n");
wr32(&pf->hw, I40E_PFINT_DYN_CTL0,
(I40E_PFINT_DYN_CTL0_INTENA_MASK |
I40E_PFINT_DYN_CTL0_SWINT_TRIG_MASK));
I40E_PFINT_DYN_CTL0_SWINT_TRIG_MASK |
I40E_PFINT_DYN_CTL0_ITR_INDX_MASK |
I40E_PFINT_DYN_CTL0_SW_ITR_INDX_ENA_MASK |
I40E_PFINT_DYN_CTL0_SW_ITR_INDX_MASK));
usleep_range(1000, 2000);
*data = (swc_old == pf->sw_int_count);
......
......@@ -5565,11 +5565,17 @@ static void i40e_check_hang_subtask(struct i40e_pf *pf)
if (!(pf->flags & I40E_FLAG_MSIX_ENABLED)) {
wr32(&vsi->back->hw, I40E_PFINT_DYN_CTL0,
(I40E_PFINT_DYN_CTL0_INTENA_MASK |
I40E_PFINT_DYN_CTL0_SWINT_TRIG_MASK));
I40E_PFINT_DYN_CTL0_SWINT_TRIG_MASK |
I40E_PFINT_DYN_CTL0_ITR_INDX_MASK |
I40E_PFINT_DYN_CTL0_SW_ITR_INDX_ENA_MASK |
I40E_PFINT_DYN_CTL0_SW_ITR_INDX_MASK));
} else {
u16 vec = vsi->base_vector - 1;
u32 val = (I40E_PFINT_DYN_CTLN_INTENA_MASK |
I40E_PFINT_DYN_CTLN_SWINT_TRIG_MASK);
I40E_PFINT_DYN_CTLN_SWINT_TRIG_MASK |
I40E_PFINT_DYN_CTLN_ITR_INDX_MASK |
I40E_PFINT_DYN_CTLN_SW_ITR_INDX_ENA_MASK |
I40E_PFINT_DYN_CTLN_SW_ITR_INDX_MASK);
for (i = 0; i < vsi->num_q_vectors; i++, vec++)
wr32(&vsi->back->hw,
I40E_PFINT_DYN_CTLN(vec), val);
......
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