提交 52f843f6 编写于 作者: D Daniel Vetter

drm/i915: Wire up gen2 CRC support

Really simple, and we don't even have working frame numbers.

v2: Actually enable it ...

v3: Review from Ville:
- Unconditionally enable the border in the CRC checksum for
  consistency with gen3+.
- Handle the "none" source to be able to disable the CRC machinery
  again.

Cc: Ville Syrjälä <ville.syrjala@linux.intel.com>
Reviewed-by: NVille Syrjälä <ville.syrjala@linux.intel.com>
Signed-off-by: NDaniel Vetter <daniel.vetter@ffwll.ch>
上级 4b79ebf7
......@@ -1947,6 +1947,23 @@ static int display_crc_ctl_open(struct inode *inode, struct file *file)
return single_open(file, display_crc_ctl_show, dev);
}
static int i8xx_pipe_crc_ctl_reg(enum intel_pipe_crc_source source,
uint32_t *val)
{
switch (source) {
case INTEL_PIPE_CRC_SOURCE_PIPE:
*val = PIPE_CRC_ENABLE | PIPE_CRC_INCLUDE_BORDER_I8XX;
break;
case INTEL_PIPE_CRC_SOURCE_NONE:
*val = 0;
break;
default:
return -EINVAL;
}
return 0;
}
static int i9xx_pipe_crc_ctl_reg(struct drm_device *dev,
enum intel_pipe_crc_source source,
uint32_t *val)
......@@ -2039,7 +2056,7 @@ static int pipe_crc_set_source(struct drm_device *dev, enum pipe pipe,
u32 val;
int ret;
if (!(INTEL_INFO(dev)->gen >= 3 && !IS_VALLEYVIEW(dev)))
if (IS_VALLEYVIEW(dev))
return -ENODEV;
if (pipe_crc->source == source)
......@@ -2049,7 +2066,9 @@ static int pipe_crc_set_source(struct drm_device *dev, enum pipe pipe,
if (pipe_crc->source && source)
return -EINVAL;
if (INTEL_INFO(dev)->gen < 5)
if (IS_GEN2(dev))
ret = i8xx_pipe_crc_ctl_reg(source, &val);
else if (INTEL_INFO(dev)->gen < 5)
ret = i9xx_pipe_crc_ctl_reg(dev, source, &val);
else if (IS_GEN5(dev) || IS_GEN6(dev))
ret = ilk_pipe_crc_ctl_reg(source, &val);
......
......@@ -1873,6 +1873,7 @@
#define PIPE_CRC_SOURCE_DP_B_G4X (6 << 28)
#define PIPE_CRC_SOURCE_DP_C_G4X (7 << 28)
/* gen2 doesn't have source selection bits */
#define PIPE_CRC_INCLUDE_BORDER_I8XX (1 << 30)
#define _PIPE_CRC_RES_1_A_IVB 0x60064
#define _PIPE_CRC_RES_2_A_IVB 0x60068
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册