提交 4fe36226 编写于 作者: P Paul M Stillwell Jr 提交者: Tony Nguyen

ice: remove return variable

We were saving the return value from ice_vsi_manage_rss_lut(), but
the errors from that function are not critical so change it to
return void and remove the code that saved the value.
Signed-off-by: NPaul M Stillwell Jr <paul.m.stillwell.jr@intel.com>
Tested-by: NTony Brelinski <tonyx.brelinski@intel.com>
Signed-off-by: NTony Nguyen <anthony.l.nguyen@intel.com>
上级 b370245b
......@@ -1313,14 +1313,13 @@ static int ice_vsi_alloc_rings(struct ice_vsi *vsi)
* LUT, while in the event of enable request for RSS, it will reconfigure RSS
* LUT.
*/
int ice_vsi_manage_rss_lut(struct ice_vsi *vsi, bool ena)
void ice_vsi_manage_rss_lut(struct ice_vsi *vsi, bool ena)
{
int err = 0;
u8 *lut;
lut = kzalloc(vsi->rss_table_size, GFP_KERNEL);
if (!lut)
return -ENOMEM;
return;
if (ena) {
if (vsi->rss_lut_user)
......@@ -1330,9 +1329,8 @@ int ice_vsi_manage_rss_lut(struct ice_vsi *vsi, bool ena)
vsi->rss_size);
}
err = ice_set_rss_lut(vsi, lut, vsi->rss_table_size);
ice_set_rss_lut(vsi, lut, vsi->rss_table_size);
kfree(lut);
return err;
}
/**
......
......@@ -85,7 +85,7 @@ void ice_vsi_free_rx_rings(struct ice_vsi *vsi);
void ice_vsi_free_tx_rings(struct ice_vsi *vsi);
int ice_vsi_manage_rss_lut(struct ice_vsi *vsi, bool ena);
void ice_vsi_manage_rss_lut(struct ice_vsi *vsi, bool ena);
void ice_update_tx_ring_stats(struct ice_ring *ring, u64 pkts, u64 bytes);
......
......@@ -5112,10 +5112,10 @@ ice_set_features(struct net_device *netdev, netdev_features_t features)
* separate if/else statements to guarantee each feature is checked
*/
if (features & NETIF_F_RXHASH && !(netdev->features & NETIF_F_RXHASH))
ret = ice_vsi_manage_rss_lut(vsi, true);
ice_vsi_manage_rss_lut(vsi, true);
else if (!(features & NETIF_F_RXHASH) &&
netdev->features & NETIF_F_RXHASH)
ret = ice_vsi_manage_rss_lut(vsi, false);
ice_vsi_manage_rss_lut(vsi, false);
if ((features & NETIF_F_HW_VLAN_CTAG_RX) &&
!(netdev->features & NETIF_F_HW_VLAN_CTAG_RX))
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册