提交 4101e976 编写于 作者: J Julia Lawall 提交者: David S. Miller

drivers/isdn: delete double assignment

Delete successive assignments to the same location.  In the first case, the
hscx array has two elements, so change the assignment to initialize the
second one.  In the second case, the two assignments are simply identical.
Furthermore, neither is necessary, because the effect of the assignment is
only visible in the next line, in the assignment in the if test.  The patch
inlines the right hand side value in the latter assignment and pulls that
assignment out of the if test.

A simplified version of the semantic match that finds this problem is as
follows: (http://coccinelle.lip6.fr/)

// <smpl>
@@
expression i;
@@

*i = ...;
 i = ...;
// </smpl>
Signed-off-by: NJulia Lawall <julia@diku.dk>
Signed-off-by: NDavid S. Miller <davem@davemloft.net>
上级 13c3ab86
......@@ -563,7 +563,7 @@ reset_inf(struct inf_hw *hw)
mdelay(10);
hw->ipac.isac.adf2 = 0x87;
hw->ipac.hscx[0].slot = 0x1f;
hw->ipac.hscx[0].slot = 0x23;
hw->ipac.hscx[1].slot = 0x23;
break;
case INF_GAZEL_R753:
val = inl((u32)hw->cfg.start + GAZEL_CNTRL);
......
......@@ -164,11 +164,9 @@ l3_1tr6_setup(struct l3_process *pc, u_char pr, void *arg)
char tmp[80];
struct sk_buff *skb = arg;
p = skb->data;
/* Channel Identification */
p = skb->data;
if ((p = findie(p, skb->len, WE0_chanID, 0))) {
p = findie(skb->data, skb->len, WE0_chanID, 0);
if (p) {
if (p[1] != 1) {
l3_1tr6_error(pc, "setup wrong chanID len", skb);
return;
......
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