提交 38dd9c02 编写于 作者: R Roy Franz 提交者: Matt Fleming

efi: Enforce minimum alignment of 1 page on allocations.

The efi_high_alloc() and efi_low_alloc() functions
use the EFI_ALLOCATE_ADDRESS option to the EFI
function allocate_pages(), which requires a minimum
of page alignment, and rejects all other requests.
The existing code could fail to allocate depending
on allocation size, as although repeated allocation
attempts were made, none were guaranteed to be page
aligned.
Signed-off-by: NRoy Franz <roy.franz@linaro.org>
Acked-by: NMark Salter <msalter@redhat.com>
Reviewed-by: NGrant Likely <grant.likely@linaro.org>
Signed-off-by: NMatt Fleming <matt.fleming@intel.com>
上级 40e4530a
......@@ -101,6 +101,14 @@ static efi_status_t efi_high_alloc(efi_system_table_t *sys_table_arg,
if (status != EFI_SUCCESS)
goto fail;
/*
* Enforce minimum alignment that EFI requires when requesting
* a specific address. We are doing page-based allocations,
* so we must be aligned to a page.
*/
if (align < EFI_PAGE_SIZE)
align = EFI_PAGE_SIZE;
nr_pages = round_up(size, EFI_PAGE_SIZE) / EFI_PAGE_SIZE;
again:
for (i = 0; i < map_size / desc_size; i++) {
......@@ -179,6 +187,14 @@ static efi_status_t efi_low_alloc(efi_system_table_t *sys_table_arg,
if (status != EFI_SUCCESS)
goto fail;
/*
* Enforce minimum alignment that EFI requires when requesting
* a specific address. We are doing page-based allocations,
* so we must be aligned to a page.
*/
if (align < EFI_PAGE_SIZE)
align = EFI_PAGE_SIZE;
nr_pages = round_up(size, EFI_PAGE_SIZE) / EFI_PAGE_SIZE;
for (i = 0; i < map_size / desc_size; i++) {
efi_memory_desc_t *desc;
......
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