未验证 提交 2dbf0855 编写于 作者: M Michał Mirosław 提交者: Mark Brown

regulator: cleanup regulator_ena_gpio_free()

Since only regulator_ena_gpio_request() allocates rdev->ena_pin, and it
guarantees that same gpiod gets same pin structure, it is enough to
compare just the pointers. Also we know there can be only one matching
entry on the list. Rework the code take advantage of the facts.
Signed-off-by: NMichał Mirosław <mirq-linux@rere.qmqm.pl>
Link: https://lore.kernel.org/r/3ff002c7aa3bd774491af4291a9df23541fcf892.1597195321.git.mirq-linux@rere.qmqm.plSigned-off-by: NMark Brown <broonie@kernel.org>
上级 d3c73156
......@@ -2287,19 +2287,19 @@ static void regulator_ena_gpio_free(struct regulator_dev *rdev)
/* Free the GPIO only in case of no use */
list_for_each_entry_safe(pin, n, &regulator_ena_gpio_list, list) {
if (pin->gpiod == rdev->ena_pin->gpiod) {
if (pin->request_count <= 1) {
pin->request_count = 0;
gpiod_put(pin->gpiod);
list_del(&pin->list);
kfree(pin);
rdev->ena_pin = NULL;
return;
} else {
pin->request_count--;
}
}
if (pin != rdev->ena_pin)
continue;
if (--pin->request_count)
break;
gpiod_put(pin->gpiod);
list_del(&pin->list);
kfree(pin);
break;
}
rdev->ena_pin = NULL;
}
/**
......
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