提交 1d23c451 编写于 作者: O Oleg Nesterov 提交者: Ingo Molnar

x86/fpu: Factor out memset(xstate, 0) in fpu_finit() paths

fx_finit() has two users but only fpu_finit() needs to clear
xstate, alloc_bootmem_align() in setup_init_fpu_buf() returns
zero-filled memory.

And note that both memset()'s look confusing. Yes, offsetof() is
0 for ->fxsave or ->fsave, but it would be cleaner to turn
them into a single memset() which zeroes fpu->state.
Signed-off-by: NOleg Nesterov <oleg@redhat.com>
Signed-off-by: NBorislav Petkov <bp@suse.de>
Acked-by: NRik van Riel <riel@redhat.com>
Cc: Andy Lutomirski <luto@amacapital.net>
Cc: Borislav Petkov <bp@alien8.de>
Cc: H. Peter Anvin <hpa@zytor.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Tavis Ormandy <taviso@google.com>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: http://lkml.kernel.org/r/1425967585-4725-2-git-send-email-bp@alien8.de
Link: http://lkml.kernel.org/r/20150302183257.GC23085@redhat.comSigned-off-by: NIngo Molnar <mingo@kernel.org>
上级 e7f180dc
...@@ -135,7 +135,6 @@ static __always_inline __pure bool use_fxsr(void) ...@@ -135,7 +135,6 @@ static __always_inline __pure bool use_fxsr(void)
static inline void fx_finit(struct i387_fxsave_struct *fx) static inline void fx_finit(struct i387_fxsave_struct *fx)
{ {
memset(fx, 0, xstate_size);
fx->cwd = 0x37f; fx->cwd = 0x37f;
fx->mxcsr = MXCSR_DEFAULT; fx->mxcsr = MXCSR_DEFAULT;
} }
......
...@@ -224,11 +224,12 @@ void fpu_finit(struct fpu *fpu) ...@@ -224,11 +224,12 @@ void fpu_finit(struct fpu *fpu)
return; return;
} }
memset(fpu->state, 0, xstate_size);
if (cpu_has_fxsr) { if (cpu_has_fxsr) {
fx_finit(&fpu->state->fxsave); fx_finit(&fpu->state->fxsave);
} else { } else {
struct i387_fsave_struct *fp = &fpu->state->fsave; struct i387_fsave_struct *fp = &fpu->state->fsave;
memset(fp, 0, xstate_size);
fp->cwd = 0xffff037fu; fp->cwd = 0xffff037fu;
fp->swd = 0xffff0000u; fp->swd = 0xffff0000u;
fp->twd = 0xffffffffu; fp->twd = 0xffffffffu;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册