提交 0a6c2e9e 编写于 作者: T Thomas Gleixner 提交者: Borislav Petkov

x86/fpu/signal: Split out the direct restore code

Prepare for smarter failure handling of the direct restore.
Signed-off-by: NThomas Gleixner <tglx@linutronix.de>
Signed-off-by: NBorislav Petkov <bp@suse.de>
Link: https://lkml.kernel.org/r/20210623121457.493455414@linutronix.de
上级 cdcec1b7
......@@ -250,10 +250,8 @@ sanitize_restored_user_xstate(union fpregs_state *state,
}
}
/*
* Restore the FPU state directly from the userspace signal frame.
*/
static int restore_fpregs_from_user(void __user *buf, u64 xrestore, bool fx_only)
static int __restore_fpregs_from_user(void __user *buf, u64 xrestore,
bool fx_only)
{
if (use_xsave()) {
u64 init_bv = xfeatures_mask_uabi() & ~xrestore;
......@@ -274,6 +272,57 @@ static int restore_fpregs_from_user(void __user *buf, u64 xrestore, bool fx_only
}
}
static int restore_fpregs_from_user(void __user *buf, u64 xrestore, bool fx_only)
{
struct fpu *fpu = &current->thread.fpu;
int ret;
fpregs_lock();
pagefault_disable();
ret = __restore_fpregs_from_user(buf, xrestore, fx_only);
pagefault_enable();
if (unlikely(ret)) {
/*
* The above did an FPU restore operation, restricted to
* the user portion of the registers, and failed, but the
* microcode might have modified the FPU registers
* nevertheless.
*
* If the FPU registers do not belong to current, then
* invalidate the FPU register state otherwise the task
* might preempt current and return to user space with
* corrupted FPU registers.
*
* In case current owns the FPU registers then no further
* action is required. The fixup in the slow path will
* handle it correctly.
*/
if (test_thread_flag(TIF_NEED_FPU_LOAD))
__cpu_invalidate_fpregs_state();
fpregs_unlock();
return ret;
}
/*
* Restore supervisor states: previous context switch etc has done
* XSAVES and saved the supervisor states in the kernel buffer from
* which they can be restored now.
*
* It would be optimal to handle this with a single XRSTORS, but
* this does not work because the rest of the FPU registers have
* been restored from a user buffer directly. The single XRSTORS
* happens below, when the user buffer has been copied to the
* kernel one.
*/
if (test_thread_flag(TIF_NEED_FPU_LOAD) && xfeatures_mask_supervisor())
os_xrstor(&fpu->state.xsave, xfeatures_mask_supervisor());
fpregs_mark_activate();
fpregs_unlock();
return 0;
}
static int __fpu_restore_sig(void __user *buf, void __user *buf_fx,
bool ia32_fxstate)
{
......@@ -298,61 +347,16 @@ static int __fpu_restore_sig(void __user *buf, void __user *buf_fx,
user_xfeatures = fx_sw_user.xfeatures;
}
if (!ia32_fxstate) {
if (likely(!ia32_fxstate)) {
/*
* Attempt to restore the FPU registers directly from user
* memory. For that to succeed, the user access cannot cause
* page faults. If it does, fall back to the slow path below,
* going through the kernel buffer with the enabled pagefault
* handler.
* memory. For that to succeed, the user access cannot cause page
* faults. If it does, fall back to the slow path below, going
* through the kernel buffer with the enabled pagefault handler.
*/
fpregs_lock();
pagefault_disable();
ret = restore_fpregs_from_user(buf_fx, user_xfeatures, fx_only);
pagefault_enable();
if (!ret) {
/*
* Restore supervisor states: previous context switch
* etc has done XSAVES and saved the supervisor states
* in the kernel buffer from which they can be restored
* now.
*
* We cannot do a single XRSTORS here - which would
* be nice - because the rest of the FPU registers are
* being restored from a user buffer directly. The
* single XRSTORS happens below, when the user buffer
* has been copied to the kernel one.
*/
if (test_thread_flag(TIF_NEED_FPU_LOAD) &&
xfeatures_mask_supervisor()) {
os_xrstor(&fpu->state.xsave,
xfeatures_mask_supervisor());
}
fpregs_mark_activate();
fpregs_unlock();
if (likely(!ret))
return 0;
}
/*
* The above did an FPU restore operation, restricted to
* the user portion of the registers, and failed, but the
* microcode might have modified the FPU registers
* nevertheless.
*
* If the FPU registers do not belong to current, then
* invalidate the FPU register state otherwise the task might
* preempt current and return to user space with corrupted
* FPU registers.
*
* In case current owns the FPU registers then no further
* action is required. The fixup below will handle it
* correctly.
*/
if (test_thread_flag(TIF_NEED_FPU_LOAD))
__cpu_invalidate_fpregs_state();
fpregs_unlock();
} else {
/*
* For 32-bit frames with fxstate, copy the fxstate so it can
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册