提交 02357bdc 编写于 作者: B Bandan Das 提交者: Paolo Bonzini

KVM: emulate: cleanup decode_modrm

Remove the if conditional - that will help us avoid
an "else initialize to 0" Also, rearrange operators
for slightly better code.
Signed-off-by: NBandan Das <bsd@redhat.com>
Signed-off-by: NPaolo Bonzini <pbonzini@redhat.com>
上级 685bbf4a
......@@ -1066,19 +1066,17 @@ static int decode_modrm(struct x86_emulate_ctxt *ctxt,
struct operand *op)
{
u8 sib;
int index_reg = 0, base_reg = 0, scale;
int index_reg, base_reg, scale;
int rc = X86EMUL_CONTINUE;
ulong modrm_ea = 0;
if (ctxt->rex_prefix) {
ctxt->modrm_reg = (ctxt->rex_prefix & 4) << 1; /* REX.R */
index_reg = (ctxt->rex_prefix & 2) << 2; /* REX.X */
ctxt->modrm_rm = base_reg = (ctxt->rex_prefix & 1) << 3; /* REG.B */
}
ctxt->modrm_reg = ((ctxt->rex_prefix << 1) & 8); /* REX.R */
index_reg = (ctxt->rex_prefix << 2) & 8; /* REX.X */
base_reg = (ctxt->rex_prefix << 3) & 8; /* REX.B */
ctxt->modrm_mod |= (ctxt->modrm & 0xc0) >> 6;
ctxt->modrm_mod = (ctxt->modrm & 0xc0) >> 6;
ctxt->modrm_reg |= (ctxt->modrm & 0x38) >> 3;
ctxt->modrm_rm |= (ctxt->modrm & 0x07);
ctxt->modrm_rm = base_reg | (ctxt->modrm & 0x07);
ctxt->modrm_seg = VCPU_SREG_DS;
if (ctxt->modrm_mod == 3 || (ctxt->d & NoMod)) {
......
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