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由 Roel Kluin 提交于
A definition like: #define regs_return_value(regs) ((regs)->regs[0]) called with regs_return_value(foo) will be preprocessed to: ((foo)->foo[0]) ^^^ So to fix this to ensure the preprocessor compiles such calls correctly. Signed-off-by: NRoel Kluin <roel.kluin@gmail.com> Signed-off-by: NPaul Mundt <lethal@linux-sh.org>
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