-
由 Laxman Dewangan 提交于
Use for_each_available_child_of_node() for iterating over each available child instead of iterating over each child and then checking their status. Signed-off-by: NLaxman Dewangan <ldewangan@nvidia.com> Signed-off-by: NEduardo Valentin <edubezval@gmail.com>
42bbe400