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由 Steven Rostedt 提交于
When a long value is read on 32 bit machines for 64 bit output, the parsing needs to change "%lu" into "%llu", as the value is read natively. Unfortunately, if "%llu" is already there, the code will add another "l" to it and fail to parse it properly. Signed-off-by: NSteven Rostedt <rostedt@goodmis.org> Acked-by: NNamhyung Kim <namhyung@kernel.org> Cc: stable@vger.kernel.org Link: http://lkml.kernel.org/r/20151116172516.4b79b109@gandalf.local.homeSigned-off-by: NArnaldo Carvalho de Melo <acme@redhat.com>
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