This time of the type:

 skb->nh.iph = (struct iphdr *)skb->data;

That is completely equivalent to:

 skb->nh.raw = skb->data;

Wonder why people love casts... :-)
Signed-off-by: NArnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: NDavid S. Miller <davem@davemloft.net>