-
由 Andy Whitcroft 提交于
A do without braces '{' may trigger a false possible type 'do' and then this may be interpreted as an external definition of foo(): do foo(); while (bar); Add do to the type exclusions. Fix up tests so we can check for them. Signed-off-by: NAndy Whitcroft <apw@shadowen.org> Signed-off-by: NAndrew Morton <akpm@linux-foundation.org> Signed-off-by: NLinus Torvalds <torvalds@linux-foundation.org>
0776e594