提交 d382e1ae 编写于 作者: S sherman

8028321: Fix for String.split() empty input sequence/JDK-6559590 triggers regression

Summary: to undo the change for 6559590
Reviewed-by: darcy
上级 82b7b483
......@@ -2235,8 +2235,7 @@ public final class String
* expression or is terminated by the end of the string. The substrings in
* the array are in the order in which they occur in this string. If the
* expression does not match any part of the input then the resulting array
* has just one element, namely this string. A zero-length input sequence
* always results zero-length resulting array.
* has just one element, namely this string.
*
* <p> When there is a positive-width match at the beginning of this
* string then an empty leading substring is included at the beginning
......@@ -2331,8 +2330,6 @@ public final class String
(ch < Character.MIN_HIGH_SURROGATE ||
ch > Character.MAX_LOW_SURROGATE))
{
if (value.length == 0)
return new String[0];
int off = 0;
int next = 0;
boolean limited = limit > 0;
......
......@@ -1144,8 +1144,7 @@ public final class Pattern
* substrings in the array are in the order in which they occur in the
* input. If this pattern does not match any subsequence of the input then
* the resulting array has just one element, namely the input sequence in
* string form. A zero-length input sequence always results zero-length
* resulting array.
* string form.
*
* <p> When there is a positive-width match at the beginning of the input
* sequence then an empty leading substring is included at the beginning
......@@ -1201,8 +1200,6 @@ public final class Pattern
* around matches of this pattern
*/
public String[] split(CharSequence input, int limit) {
if (input.length() == 0)
return new String[0];
int index = 0;
boolean matchLimited = limit > 0;
ArrayList<String> matchList = new ArrayList<>();
......@@ -5767,15 +5764,13 @@ NEXT: while (i <= last) {
* input sequence that is terminated by another subsequence that matches
* this pattern or is terminated by the end of the input sequence. The
* substrings in the stream are in the order in which they occur in the
* input. Trailing empty strings will be discarded and not encountered in
* input. Trailing empty strings will be discarded and not encountered in
* the stream.
*
* <p> If this pattern does not match any subsequence of the input then
* the resulting stream has just one element, namely the input sequence in
* string form.
*
* <p> A zero-length input sequence always results an empty stream.
*
* <p> When there is a positive-width match at the beginning of the input
* sequence then an empty leading substring is included at the beginning
* of the stream. A zero-width match at the beginning however never produces
......
......@@ -81,8 +81,10 @@ public class Split {
// split() now returns 0-length for empty source "" see #6559590
source = "";
String[] result = source.split("e", 0);
if (result.length != 0)
if (result.length != 1)
throw new RuntimeException("String.split failure 8");
if (!result[0].equals(source))
throw new RuntimeException("String.split failure 9");
// check fastpath of String.split()
source = "0123456789abcdefgABCDEFG";
......
......@@ -1781,7 +1781,9 @@ public class RegExTest {
// split() now returns 0-length for empty source "" see #6559590
source = "";
result = source.split("e", 0);
if (result.length != 0)
if (result.length != 1)
failCount++;
if (!result[0].equals(source))
failCount++;
// Check both split() and splitAsStraem(), especially for zero-lenth
......@@ -1817,8 +1819,8 @@ public class RegExTest {
{ "Abc", "Efg", "Hij" },
{ "Abc", "Efg" },
{ "Abc" },
{},
{},
{ "" },
{ "" },
{ "awgqwefg1fefw", "vssv1vvv1" },
{ "afbfq", "bgwgb", "wngnwggw", "", "hjrnhneerh" },
......@@ -1826,7 +1828,7 @@ public class RegExTest {
{ "a\u4ebafg", "fefw\u4eba4\u9f9cvssv\u9f9c", "v\u672c\u672cvv" },
{ "1", "23", "456", "7890" },
{ "1", "23\u9f9c\u672c\u672c", "456", "\u9f9c\u672c7890" },
{},
{ "" },
{ "This", "is", "testing", "", "with", "different", "separators" },
{ "b", "", ":and:f" },
{ "b", "", "", "", "", ":and:f" },
......@@ -1834,11 +1836,15 @@ public class RegExTest {
};
for (int i = 0; i < input.length; i++) {
pattern = Pattern.compile(input[i][0]);
if (!Arrays.equals(pattern.split(input[i][1]), expected[i]))
if (!Arrays.equals(pattern.split(input[i][1]), expected[i])) {
failCount++;
if (!Arrays.equals(pattern.splitAsStream(input[i][1]).toArray(),
expected[i]))
}
if (input[i][1].length() > 0 && // splitAsStream() return empty resulting
// array for zero-length input for now
!Arrays.equals(pattern.splitAsStream(input[i][1]).toArray(),
expected[i])) {
failCount++;
}
}
report("Split");
}
......
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