提交 ed10daae 编写于 作者: M Mauro Carvalho Chehab

V4L/DVB (12273): em28xx-video: rename ac97 audio controls to better document it

As em28xx chip has nothing to do with volume/mute controls, rename those
controls to properly indicate that they control the companion AC97 chip
that it is inside the boards with this chip.
Signed-off-by: NMauro Carvalho Chehab <mchehab@redhat.com>
上级 2365b2d3
......@@ -124,7 +124,7 @@ static struct em28xx_fmt format[] = {
/* supported controls */
/* Common to all boards */
static struct v4l2_queryctrl em28xx_qctrl[] = {
static struct v4l2_queryctrl ac97_qctrl[] = {
{
.id = V4L2_CID_AUDIO_VOLUME,
.type = V4L2_CTRL_TYPE_INTEGER,
......@@ -1050,9 +1050,9 @@ static int vidioc_queryctrl(struct file *file, void *priv,
qc->id = id;
if (!dev->board.has_msp34xx) {
for (i = 0; i < ARRAY_SIZE(em28xx_qctrl); i++) {
if (qc->id && qc->id == em28xx_qctrl[i].id) {
memcpy(qc, &(em28xx_qctrl[i]), sizeof(*qc));
for (i = 0; i < ARRAY_SIZE(ac97_qctrl); i++) {
if (qc->id && qc->id == ac97_qctrl[i].id) {
memcpy(qc, &(ac97_qctrl[i]), sizeof(*qc));
return 0;
}
}
......@@ -1114,10 +1114,10 @@ static int vidioc_s_ctrl(struct file *file, void *priv,
v4l2_device_call_all(&dev->v4l2_dev, 0, core, s_ctrl, ctrl);
else {
rc = 1;
for (i = 0; i < ARRAY_SIZE(em28xx_qctrl); i++) {
if (ctrl->id == em28xx_qctrl[i].id) {
if (ctrl->value < em28xx_qctrl[i].minimum ||
ctrl->value > em28xx_qctrl[i].maximum) {
for (i = 0; i < ARRAY_SIZE(ac97_qctrl); i++) {
if (ctrl->id == ac97_qctrl[i].id) {
if (ctrl->value < ac97_qctrl[i].minimum ||
ctrl->value > ac97_qctrl[i].maximum) {
rc = -ERANGE;
break;
}
......@@ -1654,9 +1654,9 @@ static int radio_queryctrl(struct file *file, void *priv,
qc->id >= V4L2_CID_LASTP1)
return -EINVAL;
for (i = 0; i < ARRAY_SIZE(em28xx_qctrl); i++) {
if (qc->id && qc->id == em28xx_qctrl[i].id) {
memcpy(qc, &(em28xx_qctrl[i]), sizeof(*qc));
for (i = 0; i < ARRAY_SIZE(ac97_qctrl); i++) {
if (qc->id && qc->id == ac97_qctrl[i].id) {
memcpy(qc, &(ac97_qctrl[i]), sizeof(*qc));
return 0;
}
}
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册