提交 c308c1b2 编写于 作者: P Pavel Emelyanov 提交者: David S. Miller

[NET]: Cleanup the allocation/freeing of the sock object

The sock object is allocated either from the generic cache with
the kmalloc, or from the proc->slab cache.

Move this logic into an isolated set of helpers and make the
sk_alloc/sk_free look a bit nicer.
Signed-off-by: NPavel Emelyanov <xemul@openvz.org>
Signed-off-by: NDavid S. Miller <davem@davemloft.net>
上级 1e2e6b89
......@@ -870,6 +870,31 @@ static void sock_copy(struct sock *nsk, const struct sock *osk)
#endif
}
static struct sock *sk_prot_alloc(struct proto *prot, gfp_t priority)
{
struct sock *sk;
struct kmem_cache *slab;
slab = prot->slab;
if (slab != NULL)
sk = kmem_cache_alloc(slab, priority);
else
sk = kmalloc(prot->obj_size, priority);
return sk;
}
static void sk_prot_free(struct proto *prot, struct sock *sk)
{
struct kmem_cache *slab;
slab = prot->slab;
if (slab != NULL)
kmem_cache_free(slab, sk);
else
kfree(sk);
}
/**
* sk_alloc - All socket objects are allocated here
* @net: the applicable net namespace
......@@ -881,14 +906,9 @@ static void sock_copy(struct sock *nsk, const struct sock *osk)
struct sock *sk_alloc(struct net *net, int family, gfp_t priority,
struct proto *prot, int zero_it)
{
struct sock *sk = NULL;
struct kmem_cache *slab = prot->slab;
if (slab != NULL)
sk = kmem_cache_alloc(slab, priority);
else
sk = kmalloc(prot->obj_size, priority);
struct sock *sk;
sk = sk_prot_alloc(prot, priority);
if (sk) {
if (zero_it) {
memset(sk, 0, prot->obj_size);
......@@ -911,10 +931,7 @@ struct sock *sk_alloc(struct net *net, int family, gfp_t priority,
return sk;
out_free:
if (slab != NULL)
kmem_cache_free(slab, sk);
else
kfree(sk);
sk_prot_free(prot, sk);
return NULL;
}
......@@ -940,10 +957,7 @@ void sk_free(struct sock *sk)
security_sk_free(sk);
put_net(sk->sk_net);
if (sk->sk_prot_creator->slab != NULL)
kmem_cache_free(sk->sk_prot_creator->slab, sk);
else
kfree(sk);
sk_prot_free(sk->sk_prot_creator, sk);
module_put(owner);
}
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册