提交 ac80a51e 编写于 作者: G Grant Likely

of/device: populate platform_device (of_device) resource table on allocation

When allocating a platform_device to represent an OF node, also allocate
space for the resource table and populate it with IRQ and reg property
information.  This change is in preparation for merging the
of_platform_bus_type with the platform_bus_type so that existing
platform_driver code can retrieve base addresses and IRQs data.

Background: a previous commit removed struct of_device and made it a
#define alias for platform_device.
Signed-off-by: NGrant Likely <grant.likely@secretlab.ca>
CC: Michal Simek <monstr@monstr.eu>
CC: Grant Likely <grant.likely@secretlab.ca>
CC: Benjamin Herrenschmidt <benh@kernel.crashing.org>
CC: Stephen Rothwell <sfr@canb.auug.org.au>
CC: microblaze-uclinux@itee.uq.edu.au
CC: linuxppc-dev@ozlabs.org
CC: devicetree-discuss@lists.ozlabs.org
上级 94c09319
......@@ -475,10 +475,35 @@ struct of_device *of_device_alloc(struct device_node *np,
struct device *parent)
{
struct of_device *dev;
dev = kzalloc(sizeof(*dev), GFP_KERNEL);
int rc, i, num_reg = 0, num_irq = 0;
struct resource *res, temp_res;
/* First count how many resources are needed */
while (of_address_to_resource(np, num_reg, &temp_res) == 0)
num_reg++;
while (of_irq_to_resource(np, num_irq, &temp_res) != NO_IRQ)
num_irq++;
/* Allocate memory for both the struct device and the resource table */
dev = kzalloc(sizeof(*dev) + (sizeof(*res) * (num_reg + num_irq)),
GFP_KERNEL);
if (!dev)
return NULL;
res = (struct resource *) &dev[1];
/* Populate the resource table */
if (num_irq || num_reg) {
dev->num_resources = num_reg + num_irq;
dev->resource = res;
for (i = 0; i < num_reg; i++, res++) {
rc = of_address_to_resource(np, i, res);
WARN_ON(rc);
}
for (i = 0; i < num_irq; i++, res++) {
rc = of_irq_to_resource(np, i, res);
WARN_ON(rc == NO_IRQ);
}
}
dev->dev.of_node = of_node_get(np);
dev->dev.dma_mask = &dev->archdata.dma_mask;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册