cpuidle: poll_state: Revise loop termination condition

commit 01bad1c6896db021db82042e71c2bf1f97cc026b upstream

If need_resched() returns "false", breaking out of the loop in
poll_idle() will cause a new idle state to be selected, so in fact
it usually doesn't make sense to spin in it longer than the target
residency of the second state.  [Note that the "polling" state is
used only if there is at least one "real" state defined in addition
to it, so the second state is always there.]  On the other hand,
breaking out of it early (say in case the next state is disabled)
shouldn't hurt as it is polling anyway.

For this reason, make the loop in poll_idle() break if the CPU has
been spinning longer than the target residency of the second state
(the "polling" state can only be state[0]).
Signed-off-by: NRafael J. Wysocki <rafael.j.wysocki@intel.com>
Signed-off-by: NYihao Wu <wuyihao@linux.alibaba.com>
Acked-by: NMichael Wang <yun.wang@linux.alibaba.com>

drivers/cpuidle/poll_state.c

@@ -9,7 +9,6 @@
 #include <linux/sched/clock.h>
 #include <linux/sched/idle.h>
 
-#define POLL_IDLE_TIME_LIMIT	(TICK_NSEC / 16)
 #define POLL_IDLE_RELAX_COUNT	200
 
 static int __cpuidle poll_idle(struct cpuidle_device *dev,
@@ -21,6 +20,7 @@ static int __cpuidle poll_idle(struct cpuidle_device *dev,
 
 	local_irq_enable();
 	if (!current_set_polling_and_test()) {
+		u64 limit = (u64)drv->states[1].target_residency * NSEC_PER_USEC;
 		unsigned int loop_count = 0;
 
 		while (!need_resched()) {
@@ -29,7 +29,7 @@ static int __cpuidle poll_idle(struct cpuidle_device *dev,
 				continue;
 
 			loop_count = 0;
-			if (local_clock() - time_start > POLL_IDLE_TIME_LIMIT) {
+			if (local_clock() - time_start > limit) {
 				dev->poll_time_limit = true;
 				break;
 			}