提交 a0260d21 编写于 作者: B Boris BREZILLON 提交者: Brian Norris

mtd: nand: plat: use the mtd instance embedded in struct nand_chip

struct nand_chip now embeds an mtd device. Make use of this mtd instance.
Signed-off-by: NBoris Brezillon <boris.brezillon@free-electrons.com>
Signed-off-by: NBrian Norris <computersforpeace@gmail.com>
上级 4e3b6d17
......@@ -20,7 +20,6 @@
struct plat_nand_data {
struct nand_chip chip;
struct mtd_info mtd;
void __iomem *io_base;
};
......@@ -31,6 +30,7 @@ static int plat_nand_probe(struct platform_device *pdev)
{
struct platform_nand_data *pdata = dev_get_platdata(&pdev->dev);
struct plat_nand_data *data;
struct mtd_info *mtd;
struct resource *res;
const char **part_types;
int err = 0;
......@@ -58,8 +58,9 @@ static int plat_nand_probe(struct platform_device *pdev)
data->chip.priv = &data;
nand_set_flash_node(&data->chip, pdev->dev.of_node);
data->mtd.priv = &data->chip;
data->mtd.dev.parent = &pdev->dev;
mtd = nand_to_mtd(&data->chip);
mtd->priv = &data->chip;
mtd->dev.parent = &pdev->dev;
data->chip.IO_ADDR_R = data->io_base;
data->chip.IO_ADDR_W = data->io_base;
......@@ -87,21 +88,21 @@ static int plat_nand_probe(struct platform_device *pdev)
}
/* Scan to find existence of the device */
if (nand_scan(&data->mtd, pdata->chip.nr_chips)) {
if (nand_scan(mtd, pdata->chip.nr_chips)) {
err = -ENXIO;
goto out;
}
part_types = pdata->chip.part_probe_types;
err = mtd_device_parse_register(&data->mtd, part_types, NULL,
err = mtd_device_parse_register(mtd, part_types, NULL,
pdata->chip.partitions,
pdata->chip.nr_partitions);
if (!err)
return err;
nand_release(&data->mtd);
nand_release(mtd);
out:
if (pdata->ctrl.remove)
pdata->ctrl.remove(pdev);
......@@ -116,7 +117,7 @@ static int plat_nand_remove(struct platform_device *pdev)
struct plat_nand_data *data = platform_get_drvdata(pdev);
struct platform_nand_data *pdata = dev_get_platdata(&pdev->dev);
nand_release(&data->mtd);
nand_release(nand_to_mtd(&data->chip));
if (pdata->ctrl.remove)
pdata->ctrl.remove(pdev);
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册