提交 9ea81197 编写于 作者: J Jan Beulich 提交者: Arnaldo Carvalho de Melo

perf bench: Make "default" memcpy() selection actually use glibc's implementation

Since arch/x86/lib/memcpy_64.S implements not only __memcpy, but also
memcpy, without further precautions this function will get chose by the
static linker for resolving all references, and hence the "default"
measurement didn't really measure anything else than the
"x86-64-unrolled" one.

Fix this by renaming (through the pre-processor) the conflicting symbol.

On my Westmere system, the glibc variant turns out to require about 4%
less instructions, but 15% more cycles for the default 1Mb block size
measured.

Cc: Ingo Molnar <mingo@elte.hu>
Cc: Paul Mackerras <paulus@samba.org>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Link: http://lkml.kernel.org/r/4F16D6FD020000780006D72F@nat28.tlf.novell.comSigned-off-by: NJan Beulich <jbeulich@suse.com>
Signed-off-by: NArnaldo Carvalho de Melo <acme@redhat.com>
上级 0d37aa34
#define memcpy MEMCPY /* don't hide glibc's memcpy() */
#include "../../../arch/x86/lib/memcpy_64.S"
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