提交 7f05538a 编写于 作者: R Russell King 提交者: Ulf Hansson

mmc: sdhci: fix data timeout (part 2)

The calculation for the timeout based on the number of card clocks is
incorrect.  The calculation assumed:

	timeout in microseconds = clock cycles / clock in Hz

which is clearly a several orders of magnitude wrong.  Fix this by
multiplying the clock cycles by 1000000 prior to dividing by the Hz
based clock.  Also, as per part 1, ensure that the division rounds
up.

As this needs 64-bit math via do_div(), avoid it if the clock cycles
is zero.
Signed-off-by: NRussell King <rmk+kernel@arm.linux.org.uk>
Signed-off-by: NAdrian Hunter <adrian.hunter@intel.com>
Cc: stable@vger.kernel.org # v3.15+
Tested-by: NGregory CLEMENT <gregory.clement@free-electrons.com>
Signed-off-by: NUlf Hansson <ulf.hansson@linaro.org>
上级 fafcfda9
......@@ -636,8 +636,19 @@ static u8 sdhci_calc_timeout(struct sdhci_host *host, struct mmc_command *cmd)
target_timeout = cmd->busy_timeout * 1000;
else {
target_timeout = DIV_ROUND_UP(data->timeout_ns, 1000);
if (host->clock)
target_timeout += data->timeout_clks / host->clock;
if (host->clock && data->timeout_clks) {
unsigned long long val;
/*
* data->timeout_clks is in units of clock cycles.
* host->clock is in Hz. target_timeout is in us.
* Hence, us = 1000000 * cycles / Hz. Round up.
*/
val = 1000000 * data->timeout_clks;
if (do_div(val, host->clock))
target_timeout++;
target_timeout += val;
}
}
/*
......
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