提交 5136dea5 编写于 作者: A Andrew Morton 提交者: Thomas Gleixner

x86: bitops take an unsigned long *

All (or most) other architectures do this.  So should x86.  Fix.

Cc: Andrea Arcangeli <andrea@qumranet.com>
Signed-off-by: NAndrew Morton <akpm@linux-foundation.org>
Signed-off-by: NIngo Molnar <mingo@elte.hu>
Signed-off-by: NThomas Gleixner <tglx@linutronix.de>
上级 75d3bce2
......@@ -43,7 +43,7 @@
* Note that @nr may be almost arbitrarily large; this function is not
* restricted to acting on a single-word quantity.
*/
static inline void set_bit(int nr, volatile void *addr)
static inline void set_bit(int nr, volatile unsigned long *addr)
{
asm volatile(LOCK_PREFIX "bts %1,%0" : ADDR : "Ir" (nr) : "memory");
}
......@@ -57,7 +57,7 @@ static inline void set_bit(int nr, volatile void *addr)
* If it's called on the same region of memory simultaneously, the effect
* may be that only one operation succeeds.
*/
static inline void __set_bit(int nr, volatile void *addr)
static inline void __set_bit(int nr, volatile unsigned long *addr)
{
asm volatile("bts %1,%0" : ADDR : "Ir" (nr) : "memory");
}
......@@ -72,7 +72,7 @@ static inline void __set_bit(int nr, volatile void *addr)
* you should call smp_mb__before_clear_bit() and/or smp_mb__after_clear_bit()
* in order to ensure changes are visible on other processors.
*/
static inline void clear_bit(int nr, volatile void *addr)
static inline void clear_bit(int nr, volatile unsigned long *addr)
{
asm volatile(LOCK_PREFIX "btr %1,%0" : ADDR : "Ir" (nr));
}
......@@ -85,13 +85,13 @@ static inline void clear_bit(int nr, volatile void *addr)
* clear_bit() is atomic and implies release semantics before the memory
* operation. It can be used for an unlock.
*/
static inline void clear_bit_unlock(unsigned nr, volatile void *addr)
static inline void clear_bit_unlock(unsigned nr, volatile unsigned long *addr)
{
barrier();
clear_bit(nr, addr);
}
static inline void __clear_bit(int nr, volatile void *addr)
static inline void __clear_bit(int nr, volatile unsigned long *addr)
{
asm volatile("btr %1,%0" : ADDR : "Ir" (nr));
}
......@@ -108,7 +108,7 @@ static inline void __clear_bit(int nr, volatile void *addr)
* No memory barrier is required here, because x86 cannot reorder stores past
* older loads. Same principle as spin_unlock.
*/
static inline void __clear_bit_unlock(unsigned nr, volatile void *addr)
static inline void __clear_bit_unlock(unsigned nr, volatile unsigned long *addr)
{
barrier();
__clear_bit(nr, addr);
......@@ -126,7 +126,7 @@ static inline void __clear_bit_unlock(unsigned nr, volatile void *addr)
* If it's called on the same region of memory simultaneously, the effect
* may be that only one operation succeeds.
*/
static inline void __change_bit(int nr, volatile void *addr)
static inline void __change_bit(int nr, volatile unsigned long *addr)
{
asm volatile("btc %1,%0" : ADDR : "Ir" (nr));
}
......@@ -140,7 +140,7 @@ static inline void __change_bit(int nr, volatile void *addr)
* Note that @nr may be almost arbitrarily large; this function is not
* restricted to acting on a single-word quantity.
*/
static inline void change_bit(int nr, volatile void *addr)
static inline void change_bit(int nr, volatile unsigned long *addr)
{
asm volatile(LOCK_PREFIX "btc %1,%0" : ADDR : "Ir" (nr));
}
......@@ -153,7 +153,7 @@ static inline void change_bit(int nr, volatile void *addr)
* This operation is atomic and cannot be reordered.
* It also implies a memory barrier.
*/
static inline int test_and_set_bit(int nr, volatile void *addr)
static inline int test_and_set_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -170,7 +170,7 @@ static inline int test_and_set_bit(int nr, volatile void *addr)
*
* This is the same as test_and_set_bit on x86.
*/
static inline int test_and_set_bit_lock(int nr, volatile void *addr)
static inline int test_and_set_bit_lock(int nr, volatile unsigned long *addr)
{
return test_and_set_bit(nr, addr);
}
......@@ -184,7 +184,7 @@ static inline int test_and_set_bit_lock(int nr, volatile void *addr)
* If two examples of this operation race, one can appear to succeed
* but actually fail. You must protect multiple accesses with a lock.
*/
static inline int __test_and_set_bit(int nr, volatile void *addr)
static inline int __test_and_set_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -203,7 +203,7 @@ static inline int __test_and_set_bit(int nr, volatile void *addr)
* This operation is atomic and cannot be reordered.
* It also implies a memory barrier.
*/
static inline int test_and_clear_bit(int nr, volatile void *addr)
static inline int test_and_clear_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -223,7 +223,7 @@ static inline int test_and_clear_bit(int nr, volatile void *addr)
* If two examples of this operation race, one can appear to succeed
* but actually fail. You must protect multiple accesses with a lock.
*/
static inline int __test_and_clear_bit(int nr, volatile void *addr)
static inline int __test_and_clear_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -235,7 +235,7 @@ static inline int __test_and_clear_bit(int nr, volatile void *addr)
}
/* WARNING: non atomic and it can be reordered! */
static inline int __test_and_change_bit(int nr, volatile void *addr)
static inline int __test_and_change_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -255,7 +255,7 @@ static inline int __test_and_change_bit(int nr, volatile void *addr)
* This operation is atomic and cannot be reordered.
* It also implies a memory barrier.
*/
static inline int test_and_change_bit(int nr, volatile void *addr)
static inline int test_and_change_bit(int nr, volatile unsigned long *addr)
{
int oldbit;
......@@ -266,13 +266,13 @@ static inline int test_and_change_bit(int nr, volatile void *addr)
return oldbit;
}
static inline int constant_test_bit(int nr, const volatile void *addr)
static inline int constant_test_bit(int nr, const volatile unsigned long *addr)
{
return ((1UL << (nr % BITS_PER_LONG)) &
(((unsigned long *)addr)[nr / BITS_PER_LONG])) != 0;
}
static inline int variable_test_bit(int nr, volatile const void *addr)
static inline int variable_test_bit(int nr, volatile const unsigned long *addr)
{
int oldbit;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册