提交 4c2b130c 编写于 作者: R Russell King 提交者: Herbert Xu

crypto: marvell/cesa - keep creq->state in CPU endian format at all times

Currently, we read/write the state in CPU endian, but on the final
request, we convert its endian according to the requested algorithm.
(md5 is little endian, SHA are big endian.)

Always keep creq->state in CPU native endian format, and perform the
necessary conversion when copying the hash to the result.
Signed-off-by: NRussell King <rmk+kernel@arm.linux.org.uk>
Signed-off-by: NHerbert Xu <herbert@gondor.apana.org.au>
上级 80754539
......@@ -612,7 +612,7 @@ struct mv_cesa_ahash_req {
u64 len;
int src_nents;
bool last_req;
__be32 state[8];
u32 state[8];
};
/* CESA functions */
......
......@@ -347,18 +347,21 @@ static int mv_cesa_ahash_process(struct crypto_async_request *req, u32 status)
ahashreq->nbytes - creq->cache_ptr);
if (creq->last_req) {
for (i = 0; i < digsize / 4; i++) {
/*
* Hardware provides MD5 digest in a different
* endianness than SHA-1 and SHA-256 ones.
*/
if (digsize == MD5_DIGEST_SIZE)
creq->state[i] = cpu_to_le32(creq->state[i]);
else
creq->state[i] = cpu_to_be32(creq->state[i]);
}
/*
* Hardware's MD5 digest is in little endian format, but
* SHA in big endian format
*/
if (digsize == MD5_DIGEST_SIZE) {
__le32 *result = (void *)ahashreq->result;
for (i = 0; i < digsize / 4; i++)
result[i] = cpu_to_le32(creq->state[i]);
} else {
__be32 *result = (void *)ahashreq->result;
memcpy(ahashreq->result, creq->state, digsize);
for (i = 0; i < digsize / 4; i++)
result[i] = cpu_to_be32(creq->state[i]);
}
}
return ret;
......
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