提交 37ef0341 编写于 作者: P Paul E. McKenney

documentation: Add alternative release-acquire outcome

The memory-barriers.txt discussion of local transitivity and
release-acquire chains leaves out discussion of the outcome of
the read from "u".  This commit therefore adds an outcome showing
that you can get a "1" from this read even if the release-acquire
pairs don't line up.
Reported-by: NWill Deacon <will.deacon@arm.com>
Signed-off-by: NPaul E. McKenney <paulmck@linux.vnet.ibm.com>
上级 c535cc92
......@@ -1372,6 +1372,10 @@ is possible:
r0 == 0 && r1 == 1 && r2 == 1 && r3 == 0 && r4 == 0
As an aside, the following outcome is also possible:
r0 == 0 && r1 == 1 && r2 == 1 && r3 == 0 && r4 == 0 && r5 == 1
Although cpu0(), cpu1(), and cpu2() will see their respective reads and
writes in order, CPUs not involved in the release-acquire chain might
well disagree on the order. This disagreement stems from the fact that
......
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