watchdog: sp5100_tco: Fix wrong indirect I/O access for getting value of reserved bits

In case of SB800 or later chipset and re-programming MMIO address(*),
sp5100_tco module may read incorrect value of reserved bit, because the module
reads a value from an incorrect I/O address. However, this bug doesn't cause
a problem, because when re-programming MMIO address, by chance the module
writes zero (this is BIOS's default value) to the low three bits of register.
* In most cases, PC with SB8x0 or later chipset doesn't need to re-programming
  MMIO address, because such PC can enable AcpiMmio and can use 0xfed80b00 for
  watchdog register base address.

This patch fixes this bug.

Bugzilla: https://bugzilla.kernel.org/show_bug.cgi?id=43176Signed-off-by: NTakahisa Tanaka <mc74hc00@gmail.com>
Tested-by: NPaul Menzel <paulepanter@users.sourceforge.net>
Signed-off-by: NWim Van Sebroeck <wim@iguana.be>
Cc: stable <stable@vger.kernel.org>

drivers/watchdog/sp5100_tco.c

@@ -500,14 +500,15 @@ static unsigned char sp5100_tco_setupdevice(void)
 	/* Restore to the low three bits, if chipset is SB8x0(or later) */
 	if (sp5100_tco_pci->revision >= 0x40) {
 		u8 reserved_bit;
-		reserved_bit = inb(base_addr) & 0x7;
+		outb(base_addr+0, index_reg);
+		reserved_bit = inb(data_reg) & 0x7;
 		val |= (u32)reserved_bit;
 	}
 
 	/* Re-programming the watchdog timer base address */
 	outb(base_addr+0, index_reg);
 	/* Low three bits of BASE are reserved */
-	outb((val >>  0) & 0xf8, data_reg);
+	outb((val >>  0) & 0xff, data_reg);
 	outb(base_addr+1, index_reg);
 	outb((val >>  8) & 0xff, data_reg);
 	outb(base_addr+2, index_reg);